tan(2x-π/6)≥根号3
kπ+π/2>2x-π/6≥π/3+kπ
kπ+2π/3>2x≥π/2+kπ
kπ/2+π/3>x≥π/4+kπ/2
解集为{x|kπ/2+π/3>x≥π/4+kπ/2}