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设z=sinxy+cos(x+y)则dz=
高数题,会做的帮个忙,
人气:315 ℃ 时间:2020-06-19 21:16:15
解答
dz=d(sinxy)+d(cos(x+y))
=cosxyd(xy)-sin(x+y)d(x+y)
=ycosxydx+xcosxydy-sin(x+y)dx-sin(x+y)dy
=[ycosxy-sin(x+y)]dx+[xcosxy-sin(x+y)]dy
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