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这几道数学题咋做啊
1.已知x+y+z=0,则1/(y²+z²-x²)+1/(z²+x²-y²)+1/(x²+y²-z²)= 2.若 3x-4y-z=0,2x+y-8z=0,则(x+y-z)/(x-y+z)= 3.已知a+b+c=0,且a,b,c均不为0,则a(1/b+1/c)+b(1/c+1/a)+c(1/a+1/b)=
人气:412 ℃ 时间:2020-03-22 16:15:48
解答
1.∵x+y+z=0 ∴y²+z²-x²=y²+z²-(y+z)²= -2yz 同理z²+x²-y²= -2zx x²+y²-z²= -2xy 原式=1/-2yz+ 1/-2zx+1/-2xy=(通分)-(x+y+z)/ -2xyz...
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