f(x)=sinx+sin(P+x)=sinx+sinpcosx+cospsinx=(1+cosp)sinx+sinpcosx=√[(1+cosp)²+(sinp)²]sin(x+φ)当sin(x+φ) =1 函数f(x)=sinx+sin(P+x)的最大值是√[(1+cosp)²+(sinp)²]