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(2x²+3xy-2y²)/(x²+4xy+4y²),其中2x-y=0
人气:464 ℃ 时间:2019-10-19 23:00:26
解答
2x-y=0
y=2x
(2x²+3xy-2y²)/(x²+4xy+4y²)
=(2x-y)(x+2y)/(x+2y)²
=(2x-y)/(x+2y)
=(2x-2x)/(x+2y)
=0/(x+2y)
=0
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