dy/dx=f'(e^x+x^e)*[e^x+ex^(e-1)]求过程。。。这是一个求复合函数倒数的问题。设u=e^x+x^edy/dx=dy/du*du/dxdy/du=f'(u)du/dx=e^x+ex^(e-1)dy/dx=f'(u)[e^x+ex^(e-1)] =f'(e^x+x^e)*[e^x+ex^(e-1)]