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因式分解:2x^4y^4-x^8-y^8
人气:468 ℃ 时间:2020-05-09 09:55:13
解答
2x^4y^4-x^8-y^8
=-(x^8-2x^4y^4+y^8)
=-(x^4-y^4)^2
=-(x^2+y^2)^2(x+y)^2(x-y)^2
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