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求∫1/(e^x+e^-x)dx
人气:213 ℃ 时间:2020-05-13 14:50:56
解答
∫[1/(e^x+e^-x)]dx
=∫[e^x/(e^2x+1)]
=∫[1/(e^2x+1)]d(e^x)
=arctan(e^x)+C.
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