> 数学 >
已知x2-3x+1=0,求x3+
1
x3
的值.
人气:292 ℃ 时间:2020-03-30 22:09:01
解答
∵x2-3x+1=0,
∴x+
1
x
=3,
∴x2+
1
x2
=9-2=7,
∴x3+
1
x3
=(x+
1
x
)(x2-1+
1
x2

=3×(7-1)
=18.
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版