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lim[1/2!+2/3!+…+n/(n+1)!] n→∞
人气:269 ℃ 时间:2020-05-14 01:29:25
解答
n/(n+1)!=(n+1-1)/(n+1)!=1/n!-1/(n+1)!
lim[1/2!+2/3!+…+n/(n+1)!]
=lim[(1-1/2!)+(1/2!-1/3!)+...+(1/n!-1/(n+1)!)]
=lim[1-1/(n+1)!]
=1
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