F(1,0)AB斜率k=tan60°=√3设直线AB：y= √3 (x-1)x²/3 +y²/2 =1x²/3 + 3(x-1)²/2 =111x² -18x+3=0设A(x₁,y₁) B(x₂,y₂)x₁x₂= 3/11x₁+x₂=...