1.设z=z(x,y)是由方程式e的z次方=xyz所含的隐函数,求dz 2.计算出曲面z=2-x^-y^2与xoy坐标面所围成的体积
人气:161 ℃ 时间:2019-08-22 17:03:56
解答
1 e^z=xyz
e^zz'x=yz+xyz'x z'x=yz/(xy-e^z)=yz/(xy-xyz)=z/(x-xz)
类似 z'y=z/(y-yz)
dz=[z/(x-xz)]dx+[z/(y-yz)]dy
2.立体在xoy坐标面的投影D:x^2+y^2《2
V=∫∫(2-x^2-y^2)dxdy,用极坐标
=∫(0,2π)dθ∫(0,√2)r(2-r^2)dr
=2π(2-1)
=2π
推荐
- 设z=z(x,y)是由方程式e的z次方=xyz所含的隐函数,求dz
- 设Z=f(x,y)是由方程e的z次方=xyz所确定的函数 求dz
- 设z=f(x,y)是由方程x+Y+z=(e的x次方)所确定的隐函数,求dz,
- 设Z的X次方=Y的Z次方所确定的隐函数Z=Z(X,Y),求DZ
- 设z=Z(x,y)是由方程x+Y+z=(e的x次方)所确定的隐函数,求dz
- Cars moved very slowly in the 1930s,but they A faster than in the 1920s.
- 思想品德题目:如何正确认识和对待学习中的苦与乐?上册 第二课)
- 甲乙两车相向而行,4.5小时后相遇,甲车每小时行56千米,乙车每小时行60千米.甲乙两地相距多少千米?用方程
猜你喜欢