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1.设z=z(x,y)是由方程式e的z次方=xyz所含的隐函数,求dz 2.计算出曲面z=2-x^-y^2与xoy坐标面所围成的体积
人气:161 ℃ 时间:2019-08-22 17:03:56
解答
1 e^z=xyz
e^zz'x=yz+xyz'x z'x=yz/(xy-e^z)=yz/(xy-xyz)=z/(x-xz)
类似 z'y=z/(y-yz)
dz=[z/(x-xz)]dx+[z/(y-yz)]dy
2.立体在xoy坐标面的投影D:x^2+y^2《2
V=∫∫(2-x^2-y^2)dxdy,用极坐标
=∫(0,2π)dθ∫(0,√2)r(2-r^2)dr
=2π(2-1)
=2π
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