(1)×2+(2)得
(x1+x2)＾2+2(x1+x2)+3/4=0
解为x1+x2=-1/2或x1+x2=-3/2
当x1+x2=-1/2时x1x2=-1/4,解为
(1)x1=(-1+√5)/4,x2=(-1-√5)/4
(2)x1=(-1-√5)/4,x2=(-1+√5)/4
当x1+x2=-3/2时x1x2=1/4,解为
(3)x1=(-3+√5)/4,x2=(-3-√5)/4
(4)x1=(-3-√5)/4,x2=(-3+√5)/4
方程组的解有四组为
(1)x1=(-1+√5)/4,x2=(-1-√5)/4,(2)x1=(-1-√5)/4,x2=(-1+√5)/4,(3)x1=(-3+√5)/4,x2=(-3-√5)/4,(4)x1=(-3-√5)/4,x2=(-3+√5)/4.