数学题（16x-13)/(4x-3)+（40x-43)/(8x-9)=（32x-30)/(8x-7)+（20x-24)/(4x-5_数学解答

数学题（16x-13)/(4x-3)+（40x-43)/(8x-9)=（32x-30)/(8x-7)+（20x-24)/(4x-5)
在线等··············
求过程···············

人气：116 ℃　时间：2020-03-24 06:09:15

解答

(4（4x-3）-1)/4x-3+ (5(8x-9)+2)/(8x-9) =(4(8x-7)-2)/(8x-7) +(5(4x-5)+1)/(4x-5) 整理得2/(8x-9)-1/4x-3 =1/(4x-5)- 1/(8x-7)两边分别通分得1/(4x-5)(8x-7)=1/(8x-9)(4x-3) 化简(4x-5)(8x-7)= (8...然后·········