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分解因式x²y²+xy-x²-y²+x+y+2
人气:256 ℃ 时间:2019-12-25 22:01:37
解答
x²y²+xy-x²-y²+x+y+2=(x²y²-x²-y²+1)+(xy+x+y+1)=(x²-1)(y²-1)+(x+1)(y+1)=(x+1)(x-1)(y+1)(y-1)+(x+1)(y+1)=(x+1)(y+1)[(x-1)(y-1)+1]=(x+1)(...
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