A,B 是双曲线x^2-y^2/2=1上的俩点,设A(x1,y1),B(x2,y2)则:x1^2-y1^2/2=1.(1)x2-y2^2/2=1.(2)(1)-(2)(x1+x2)(x1-x2)=[(y1+y2)(y1-y2)]/2点（1,2）是线段AB得中点 (x1+x2)/2=1(y1+y2)/2=2则直线AB的斜率K=(y1-y2)/(x1-...