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(3+1)(3x3+1)(3x3x3x3+1)(3x3x3x3x3x3x3x3+1)
人气:399 ℃ 时间:2020-06-25 01:27:45
解答
原式=(3+1)(3^2+1)(3^4+1)(3^8+1)
两边同乘以(3-1),得
(3-1)*原式=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)
=(3^4-1)(3^4+1)(3^8+1)
=(3^8-1)(3^8+1)
=3^16-1
所以,原式=(3^16-1)/(3-1)=1/2*(3^16-1)
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