(2-根号3x)^100=a0+a1x+a2x^2+a3x^3+.+a100x^100
求(1)a0
(2)a1+a2+...+a100
(3)a1+a3+...+a99
(4)(a0+a2+a4+...+a100)^2-(a1+a3+...+a99)^2
(5)|a0|+|a1|+|a2|+...+|a100|
人气:479 ℃ 时间:2020-04-16 08:46:29
解答
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