x+y+z=3(1) x+2y+3z=6(2) 2x+y+2z=5(3)解三元一次方程组_数学解答

x+y+z=3(1) x+2y+3z=6(2) 2x+y+2z=5(3)
解三元一次方程组

人气：398 ℃　时间：2020-03-26 06:03:43

解答

x=3-y-z,从而3-y-z+2y+3z=3+y+2z=62x+y+2z=6-2y-2z+y+2z=6-y= 5 y=1;x=2-z
有3+y+2z=6得4+2z=6 z=1从而x=1
即x=y=z=1