y=2sin(π/3-2x)=-2sin(2x-π/3)
在2x-π/3∈[2kπ+π/2,2kπ+3π/2]
即：x∈[kπ+5π/12,kπ+11π/6]时,函数递增
所以,y=2sin(π/3-2x)的单调增区间：[kπ+5π/12,kπ+11π/6],k∈Z