y=In √[(2x-1)/(x+1)],求导?_数学解答

y=In √[(2x-1)/(x+1)],求导?

人气：197 ℃　时间：2020-02-05 20:30:34

解答

y=ln √[(2x-1)/(x+1)]
=(1/2)(ln(2x-1)-ln(x+1))
y'=(1/2)((2/(2x-1))-(1/(x+1))
=3/(2(2x-1)(x+1))