如果x等于它的倒数,那么分式x-1分之x^2+2x-3除以x^2-3x+1分之x+3等于多少
人气:466 ℃ 时间:2019-09-26 15:42:41
解答
因为x等于它的倒数,所以得:x=1/xx^2=1x1=1(舍),x2=-1(x-1)分之(x^2+2x-3)除以(x^2-3x+1)分之(x+3)=(x-1)分之(x+3)(x-1)除以(x^2-3x+1)分之(x+3)=(x+3)除以(x^2-3x+1)分之(x+3)=(x+3)乘以(x+3)分之(x^2-3x+1)=x^2-3x+...
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