1/（X+1)(X+2）+1/(X+2))(X+3)+...+1/(X+2005)(X+2006)=1/2X+4012_数学解答

1/（X+1)(X+2）+1/(X+2))(X+3)+...+1/(X+2005)(X+2006)=1/2X+4012

人气：322 ℃　时间：2020-04-27 21:09:57

解答

1/（X+1)(X+2）+1/(X+2))(X+3)+...+1/(X+2005)(X+2006)=1/2X+4012 1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+...+1/(x+2005)-1/(x+2006)=1/2(x+2006)1/(x+1)-1/(x+2006)=(1/2)*1/(x+2006)1/(x+1)=(3/2)*1/(x+2006)3(x+1)=2(x...