若a、b、c、d是四个正数,且abcd=1.求(a/abc+ab+a+1)+(b/bcd+bc+b+1)+(c/cda+cd+c+1)+(d/dab+da+d+1)的值
人气:285 ℃ 时间:2019-10-18 03:16:17
解答
a/(abc+ab+a+1)+b/(bcd+bc+b+1)+c/(cda+cd+c+1)+d/(dab+da+d+1)=a/(1/d+ab+a+1)+b/(bcd+bc+b+1)+c/(1/b+cd+c+1)+d/(dab+da+d+1)=ad/(abd+ad+d+1)+b/(bcd+bc+b+1)+bc/(bcd+bc+b+1)+d/(dab+da+d+1)=(ad+d)/(abd+ad+d+1...
推荐
猜你喜欢
- 沿直线做匀加速运动的质点在第一个0.5s内的平均速度比它在第一个1.5s内的平均速度大2.45m/s,
- This pair of trousers ____too long and I dan't think____ me
- The clerk asked me ,"Do you want to be a volunteer ?"(合并为复合句) The clerk asked me______
- Tom didn't go to school because he didn't feel(
- 一个正方形,一边减少5厘米,另一边减少8厘米,得到一长方形,长方形的面积比正方形的面积小259平方厘米.
- 并联电路中,各支路电压之和是否等于干路电压?各支路电流之和是否等于干路电流?
- 非零自然数1,2,3,······排成一行分数,规定N组有N个自然数,即(1)(2,3)(4,5,6)······
- 在4,-1.5,0,3.7,-3分之5,20,-5分之1,-2,294中,( )是正数,( )是负数,( )是自然数