定义在非零实数集上的函数f(x)满足f(xy)=f(x)+f(y)
且f(x)是区间(0,+无穷)上的递增函数.
求:1,f(1),f(-1)的值.
2,求证:f(-x)=f(x)
3,解不等式f(2)+f(x-1/2)小于等于零.
人气:176 ℃ 时间:2019-08-21 23:01:06
解答
1.x=y=1 f(1)=0 x=-1,y=-1 f(-1)=0
2.y=-1 f(-x)=f(x)+f(-1) f(-x)=f(x)
3.f(2)+f(x-1/2)=f(2x-1)
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