已知函数f(x)=cos^2(x/2)—sin^2(x/2)-sinx.1:求f(x)的最小正周期
人气:240 ℃ 时间:2019-08-20 04:29:43
解答
cos^2x/2-sin^2x/2-sinx
=cosx-sinx
=√2(√2/2cosx-√2/2sinx)
=√2(sinπ/4cosx-cosπ/4sinx)
=√2sin(π/4-x)
T=|2π/w|
=|2π/(-1)|
=|-2π|=2π
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