a-b=√3+√2b-c=√3-√2a-c=(a-b)+(b-c)=(√3+√2)+(√3-√2)=2√3a²+b²+c²-ab-bc-ca=[(a²-2ab+b²)+(b²-2bc+c²)+(c²-2ca+a²)]=[(a-b)²+(b-c)²+(c-a)²]...