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计算:(x-1/2)(2x+1)(2x∧2+1/2)(4x∧4+1/4)(16x∧8+1/16)/(256x∧16-1/256)
人气:475 ℃ 时间:2020-04-06 01:46:38
解答
原式=(2x^2-1/2)(2x^2+1/2)×()()/(256x^16-1/256) =(4x^4-1/4)(4x^4+1/4)( )/(256x^16-1/256) =(16x^8-1/16)(16x^8+1/16)/(256x^16-1/256) =(256x^16-1/256)/(256x^16-1...
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