(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)/(256x^16+1/256)=?3Q_数学解答

(x-1/2)(2x+1)(2x^2+1/2)(4x^4+1/4)(16x^8+1/16)/(256x^16+1/256)=?3Q

人气：477 ℃　时间：2020-04-01 23:05:18

解答

（X-1/2)(2X+1)(2X^2+1/2)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256)＝{[(2X-1)(2X+1)]/2}(2X^2+1/2)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256)=(4X^2-1)(2X^2+1/2)(4X^4+1/4)(16X^8+1/16)÷（256X^16-1/256)=...