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以知AM平行BN,AC平分角MAB,BC平分角NBA 1 过点C作直线DE,分别交AM,BN于点D,E ,求证:AB=AD+BE
人气:157 ℃ 时间:2020-04-06 13:58:38
解答
延长AC交BN于点F.在△ABC和△FBC中,∠ACB = 90°= ∠FCB ,BC为公共边,∠ABC = ∠FBC ,所以,△ABC ≌ △FBC ,可得:AB = FB ,AC = FC ;则有:∠BFA = ∠BAF = ∠FAD .在△ACD和△FCE中,∠ACD = ∠FCE ,AC = FC ,∠CA...
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