因式分解：2x²+y²+3xy+4x+3y+2=-------.
人气：132 ℃ 时间：2020-03-28 01:48:10
解答
2x^2+y^2+3xy+4x+3y+2
＝2x^2+y^2+2xy+xy+2x+2x+y+2y+2
＝（2x^2＋2xy+2x）+（xy+y^2+y）+（2x+2y+2）
＝2x（x+y+1）+y（x+y+1）+2（x+y+1）
＝（x+y+1）（2x+y+2）
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