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若x+y-2=0,3a²-a-2=0,求多项式5-3a²x+ax-3a²y+ay的值.
人气:237 ℃ 时间:2019-08-28 10:41:37
解答
x+y-2=0
∴x+y=2
3a²-a-2=0
∴3a²-a=2
5-3a²x+ax-3a²y+ay
=5-3a²(x+y)+a(x+y)
=5-6a²+2a
=5-2(3a²-a)
=5-2×2
=1
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