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计算lim(x趋向于π/2)(sinx)的tanx次方怎么计算?
人气:134 ℃ 时间:2019-10-17 05:57:32
解答
解法一:∵lim(x->π/2)[(sinx-1)tanx]=lim(x->π/2){[(sinx-1)/cosx]sinx}=lim(x->π/2)[(sinx-1)/cosx]*lim(x->π/2)(sinx)=lim(x->π/2){[sin(x/2)-cos(x/2)]/[cos(x/2)+sin(x/2)]}*1=0*1=0lim(x->π/2){(sinx)^[...
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