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设X1,X2是方程2X的平方-9X+6的两个根,求X1-X2值
人气:469 ℃ 时间:2020-06-08 16:28:46
解答
ax²+bx+c=0中有:x1 +x2 =-b/a x1·x2 = c/a2X²-9X+6=0中:a=2 b=-9 c=6x1 + x2 = -b/a = 9/2x1·x2 = c/a = 3(x1 - x2)² = (x1)² - 2x1·x2 + (x2)²=(x1)² + 2x1·x2 + (x2)² -...
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