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数学
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计算2分之1ab²-3分之1a²b+6分之1ab²-3分之2ab²-4+2a²b+2,
人气:412 ℃ 时间:2020-06-29 04:34:30
解答
2分之1ab²-3分之1a²b+6分之1ab²-3分之2ab²-4+2a²b+2
原式=(2分之1ab²+6分之1ab²-3分之2ab²)+(-3分之1a²b+2a²b)-4+2
=(2分之1+6分之1-3分之2)ab²+(-3分之1+2)a²b-2
=3分之5a²b-2
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