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数学
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2lg5/lg2*2lg2/lg3*2lg3/lg5=多少,
人气:326 ℃ 时间:2020-05-09 10:19:47
解答
2lg5/lg2*2lg2/lg3*2lg3/lg5
=4lg5/lg3*2lg3/lg5
=82lg5/lg2*2lg2/lg3*2lg3/lg5=4lg5/lg3*2lg3/lg5这一步怎么来的?lg5/lg2*lg2/lg3=lg5/lg3(把lg2约分掉)2lg5/lg2*2lg2/lg3=42lg5/lg3
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(2lg5·2lg2·2lg3)/(lg5·lg2·lg3)=
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