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数学计算(有关不定积分)
∫ dx/(2*sin x/2*cos x/2)
=∫d(x/2) / (tan x/2*cos^2 x/2)
=∫d(tan x/2) / tan x/2
人气:191 ℃ 时间:2020-08-30 14:06:45
解答
∫dx/sinx sinx=2sin(x/2)cos(x/2) 倍角公式
=∫ dx/(2*sin x/2*cos x/2) dx/2=d(x/2) sin(x/2)cos(x/2)=tan(x/2)(cosx/2)^2
=∫d(x/2) / (tan x/2*cos^2 x/2) d tan(x/2)=(sec(x/2))^2dx=dx/(cos(x/2))^2
=∫d(tan x/2) / tan x/2 dln(tan(x/2)=dtan(x/2)/tan(x/2)
=ln(tan(x/2))+C
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