高一三角函数化简 sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α))
人气:256 ℃ 时间:2019-09-29 00:25:37
解答
sin^2(α)/((sinα)-(cosα))+(cosα)/(1-tan(α)) = sin^2(α)/((sinα)-(cosα))+(cosα)/(1-sin(α)/cos(α)) =sin^2(α)/((sinα)-(cosα))+cos^2(α)/(cos(α)-sin(α)) =(sin^2(α)-cos^2(α))/((sinα)-(cosα)) =((sinα)-(cosα))((sinα)+(cosα))/((sinα)-(cosα)) =sinα+cosα
推荐
猜你喜欢
- 一堆圆锥形麦堆,测底面周长12.56米,高是1.2米,已知每立方米小麦约种750千克,这堆小麦的质量是多少千克.
- 高中英语题Americans eat more than twice as many
- 《桂林山水甲天下》课文
- Can you ____some things to school?A.take B.bring C.need D.find
- 怎样背英语词组最快
- look at this picture.( )A,how a beautiful picture B,how beautiful picture C,what a beautiful picture D,what beautiful pi
- 已知扇形的周长为10cm,求扇形半径r与扇形面积S之间的函数解析式S=f(x),并确定其定义域?
- 用2,4,5,6,这4个数,经过运算后得24.加,减,乘,除,括号都可以用.而且不限次数,你能写出几组?