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一.化简.5(a+b)²-3(2a+3b)-3(a+b)²+(2a+3b)
二.已知(x-6)²+|y+1|=0,求﹙﹣x+2y/3﹚-2/3(x+1/2y)的值
人气:290 ℃ 时间:2020-02-03 14:42:28
解答
5(a+b)²-3(2a+3b)-3(a+b)²+(2a+3b)=5(a+b)^2-6a-9b-3(a+b)^2+2a+3b=2 (-2 a + a^2 - 3 b + 2 a b + b^2)(x-6)²+|y+1|=0,x=6y=-1﹙﹣x+2y/3﹚-2/3(x+1/2y)=(-6-2/3)-2/3(6-1/2)=-(31/3)
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