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log2a1+log2a2+log2a3+.+log2a10=25求a5×a6
人气:488 ℃ 时间:2020-06-16 17:54:10
解答
log2a1+log2a2+log2a3+.+log2a10
=log(2)(2a1*2a2*2a3*……2a^10)
=log(2)(2^10*a1*a2*a3……a10)
=10+log(2)(a1*a2*a3……a10)=25
log(2)(a1*a2*a3……a10)=15
a1*a2*a3……a10=2^15
若a1、a2、a3……a10是等比数列,
则a1*a2*a3……a10=(a5*a6)^5 a5*a6=2^3=8
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