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计算2005/6+2005/12+2005/20+2005/30+...+2005/(2003×2004)+1/2004
人气:144 ℃ 时间:2019-12-08 04:32:04
解答
原式=2005*(1/(2*3)+1/(3*4)+...+1/(2003*2004))+1/2004
=2005*(1/2-1/3+1/3-1/4+...+1/2003-1/2004)+1/2004
=2005*(1/2-1/2004)+1/2004
=2005/2-1
=2003/2
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