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函数f(x)=cosx+根号3sinx(0<=x<=π/2)f (x)的最小值是?
人气:422 ℃ 时间:2019-08-17 19:09:43
解答
f(x)=√3sinx+cosx
=2(√3/2sinx+1/2cosx)
=2sin(x+π/6)
0≤x≤π/2
π/6≤x≤2π/3
sint在π/6≤x≤2π/3[],先增后减,
1/2≤sin(x+π/6)≤1
1≤2sin(x+π/6)≤2
f(min)=1
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