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若π/4≤π≤π/3,则函数y=[2sin(x+π/6)]/cosx的值域是多少?
人气:420 ℃ 时间:2020-03-27 03:52:00
解答
y=2(sinxcosπ/6+cosxsinπ/6)/cosx
=2sinxcosπ/6/cosx+2cosxsinπ/6/cosx
=√3tanx+1
π/4≤x≤π/3
tanπ/4≤tanx≤tanπ/3
√3≤√3tanx≤3
√3+1≤√3tanx+1≤4
值域[√3+1,4]
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