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函数y=2sin(x+π/3),x属于[π/6,π/2]的值域
人气:451 ℃ 时间:2020-04-03 16:09:16
解答

π/6<=x<=π/2
π/2<=x+π/3<=5π/6
1/2<=sin(x+π/3)<=1
1<=2sin(x+π/3)<=2
所以函数值域为[1,2]
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