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先化简,再数值.(x^2-9/x+2)除以(x^2-6x+9/2x+4)减去(2x/x
先化简,再数值.
(x^2-9/x+2)除以(x^2-6x+9/2x+4)减去(2x/x-3),其中x等于1.
人气:321 ℃ 时间:2020-03-25 14:13:57
解答
(x^2-9/x+2)÷(x^2-6x+9/2x+4)-(2x/x-3)
=[(x-3)(x+3)/(x+2)]×[2(x+2)/(x-3)²]-2x/(x-3)
=2(x+3)/(x-3)-2x/(x-3)
=6/(x-3)
=6/(1-3)
=-3
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