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X^5+X^4-5X^3-2X^2+4X-8如何得到(X-2)(X+2)^2(X^2-X+1)
有没有固定公式及方法啊..
人气:150 ℃ 时间:2019-12-11 07:14:35
解答
X^5+X^4-5X^3-2X^2+4X-8 =(X^5-2X^4)+(3X^4-5X^3-2X^2)+4(X-2) =(X^4)(X-2)+(X^2)(3X+1)(X-2)+4(X-2) =(X-2)(X^4+3X^3+X^2+4) =(X-2)[(X^4+2X^3)+(x^3+2X^2)+(4-X^2)] =(X-2)(X+2)(X^3+X^2-X+2) =(X-2)(X+2)[(X^3+2X...
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