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x^2-(2k-1)x+k^2-k+1/4=0怎么算?
人气:347 ℃ 时间:2020-04-03 17:57:08
解答
x^2-(2k-1)x+k^2-k+1/4=x^2--2(k-1/2)x+(k-1/2)^2=(x-(k-1/2))^2=0 所以x=k-1/2
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