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用综合法证明,设a>0,b>0,且a+b=1
人气:343 ℃ 时间:2020-06-03 10:11:10
解答
(a+1/a)^2+(b+1/b)^2
≥[(a+1/a)+(b+1/b)]^2/2
=(a+(a+b)/a+b+(a+b)/b]^2/2
=(a+b+1+b/a+1+a/b)^2/2
=(3+b/a+a/b)^2/2
≥(3+2)^2/2
=25/2
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