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(sin40°×sin130°)÷(cos4175°- sin4175)        PS:分母上的4是次方
人气:403 ℃ 时间:2020-04-13 22:29:31
解答
(sin40°×sin130°)÷(cos^4 175°- sin^4 175)=sin40*sin(180-50)/[(sin175)^2+(cos175)^2][(cos175)^2-(sin175)^2]=sin40sin50/[(cos5)^2-(sin5)^2]=sin40sin50/cos(5+5)=sin40cos40/cos10=1/2sin80/sin80=1/2
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