因式分解:(a^2b^2+ab)^2-(ab+1)^2
人气:410 ℃ 时间:2020-01-31 15:43:59
解答
(a^2b^2+ab)^2-(ab+1)^2 =[(a^2b^2+ab)+(ab+1)][(a^2b^2+ab)-(ab+1)] =(a^2b^2+2ab+1)(a^2b^2-1) =(ab+1)^2(ab+1)(ab-1) =(ab+1)^3(ab-1)
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